Exam Cram Sheet680 words
Limits and Continuity: High-Stakes Exam Cram Sheet
Limits and Continuity
Limits and Continuity: Exam Cram Sheet
## Topic Weighting
| Exam Component | Weighting | Priority |
|---|---|---|
| Limits Evaluation (Algebraic/Graphing) | 35% | High |
| Continuity & Discontinuity Types | 30% | High |
| Theorems (IVT, Squeeze Theorem) | 20% | Medium |
| Precise Definition ($̵-̴) | 15% | Medium |
[!IMPORTANT] Mastery of algebraic limit laws is the foundation for almost every derivative problem later in the course. Do not skip the "indeterminate form" practice.
## Key Concepts Summary
1. The Core Definition
A limit \lim_{x \to a} f(x) = L$ exists if and only if the left-hand and right-hand limits are equal:
2. Continuity at a Point ($x=a)
A function is continuous if it passes the Three-Part Test:
- Defined: f(a) exists (no hole).
- Limit Exists: \lim_{x \to a} f(x) exists (left = right).
- Agreement: \lim_{x \to a} f(x) = f(a)$.
3. Types of Discontinuities
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4. Major Theorems
- Squeeze Theorem: If and , then .
- Intermediate Value Theorem (IVT): If is continuous on and is between and such that $f(c) = L.
## Common Pitfalls
- Don't assume that f(a)$ being defined means the limit exists (e.g., Jump Discontinuity).
- Don't apply the Quotient Law if the denominator's limit is zero. This creates an indeterminate form ($0/0$), requiring factoring or conjugates.
- Don't forget to check the continuity condition before applying IVT. If the function isn't continuous on the closed interval, the theorem fails.
- Don't confuse a limit of $\infty (the behavior) with the limit "not existing" (the value). Technically, an infinite limit does not exist as a real number, but it describes specific asymptotic behavior.
## Mnemonics / Memory Triggers
- DIC (Continuity Test):
- Defined (f(a) is a real number).
- Independent limits match (Left = Right).
- Coincident (Limit value = Function value).
- "Squeeze the Sandwich": When f(x) is trapped between two "bread" functions (gh) that meet at a point, f(x)$ has no choice but to pass through that same point.
- IVT = "The No-Teleportation Rule": If a function is continuous, it cannot "jump" over a value; it must pass through every value between the start and end points.
## Formula / Equation Sheet
| Rule Name | Mathematical Expression |
|---|---|
| Precise Definition | $0 < |
| Sum/Difference | |
| Power Rule | |
| Conjugate Trick | |
| Composite Limit | if is continuous at |
Visualizing the Precise Definition
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## Practice Set
- Algebraic Limit: Evaluate $\lim_{x \to 2} \frac{x^2 - 4}{x - 2}.
- Hint: Factor the numerator.
- Conjugate Method: Evaluate \lim_{x \to 0} \frac{\sqrt{x+1} - 1}{x}.
- Hint: Multiply by the conjugate \sqrt{x+1} + 1.
- Continuity Check: Is f(x) = \begin{cases} x+1 & x < 1 \ 5 & x = 1 \ 3-x & x > 1 \end{cases}x=1?
- Hint: Check the three-part DIC test.
- IVT Application: Show that f(x) = x^3 + x - 1 has at least one root on the interval [0, 1].
- Hint: Compare f(0)f(1).
- Squeeze Theorem: Find \lim_{x \to 0} x^2 \sin(1/x).
- Hint: Start with -1 \le \sin(1/x) \le 1.
▶Click for Quick Answers
- 4 (After canceling x-2)
- 1/2 (Rationalize numerator)
- No (Limit exists as 2, but f(1)=5; fails the Coincident test)
- Yes (f(0)=-1, f(1)=1; zero is between -1 and 1)
- 0 (Bound by -x^2x^2$)