Exam Cram Sheet680 words

Limits and Continuity: High-Stakes Exam Cram Sheet

Limits and Continuity

Limits and Continuity: Exam Cram Sheet

## Topic Weighting

Exam ComponentWeightingPriority
Limits Evaluation (Algebraic/Graphing)35%High
Continuity & Discontinuity Types30%High
Theorems (IVT, Squeeze Theorem)20%Medium
Precise Definition ($̵-̴)15%Medium

[!IMPORTANT] Mastery of algebraic limit laws is the foundation for almost every derivative problem later in the course. Do not skip the "indeterminate form" practice.


## Key Concepts Summary

1. The Core Definition

A limit \lim_{x \to a} f(x) = L$ exists if and only if the left-hand and right-hand limits are equal: limxaf(x)=limxa+f(x)=L\lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x) = L

2. Continuity at a Point ($x=a)

A function is continuous if it passes the Three-Part Test:

  1. Defined: f(a) exists (no hole).
  2. Limit Exists: \lim_{x \to a} f(x) exists (left = right).
  3. Agreement: \lim_{x \to a} f(x) = f(a)$.

3. Types of Discontinuities

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4. Major Theorems

  • Squeeze Theorem: If g(x)f(x)h(x)g(x) \le f(x) \le h(x) and limxag(x)=L=limxah(x)\lim_{x \to a} g(x) = L = \lim_{x \to a} h(x), then limxaf(x)=L\lim_{x \to a} f(x) = L.
  • Intermediate Value Theorem (IVT): If ff is continuous on [a,b][a, b] and LL is between f(a)f(a) and f(b),thereexistsatleastonec(a,b)f(b), there exists at least one c \in (a, b) such that $f(c) = L.

## Common Pitfalls

  • Don't assume that f(a)$ being defined means the limit exists (e.g., Jump Discontinuity).
  • Don't apply the Quotient Law if the denominator's limit is zero. This creates an indeterminate form ($0/0$), requiring factoring or conjugates.
  • Don't forget to check the continuity condition before applying IVT. If the function isn't continuous on the closed interval, the theorem fails.
  • Don't confuse a limit of $\infty (the behavior) with the limit "not existing" (the value). Technically, an infinite limit does not exist as a real number, but it describes specific asymptotic behavior.

## Mnemonics / Memory Triggers

  • DIC (Continuity Test):
    • Defined (f(a) is a real number).
    • Independent limits match (Left = Right).
    • Coincident (Limit value = Function value).
  • "Squeeze the Sandwich": When f(x) is trapped between two "bread" functions (gandandh) that meet at a point, f(x)$ has no choice but to pass through that same point.
  • IVT = "The No-Teleportation Rule": If a function is continuous, it cannot "jump" over a value; it must pass through every value between the start and end points.

## Formula / Equation Sheet

Rule NameMathematical Expression
Precise Definition$0 <
Sum/Differencelim[f(x)±g(x)]=limf(x)±limg(x)\lim [f(x) \pm g(x)] = \lim f(x) \pm \lim g(x)
Power Rulelim[f(x)]n=[limf(x)]n\lim [f(x)]^n = [\lim f(x)]^n
Conjugate Trick(ab)(a+b)=ab2(\sqrt{a}-b)(\sqrt{a}+b) = a - b^2
Composite Limitlimxaf(g(x))=f(limxag(g(x)))\lim_{x \to a} f(g(x)) = f(\lim_{x \to a} g(g(x))) if ff is continuous at LL

Visualizing the Precise Definition

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## Practice Set

  1. Algebraic Limit: Evaluate $\lim_{x \to 2} \frac{x^2 - 4}{x - 2}.
    • Hint: Factor the numerator.
  2. Conjugate Method: Evaluate \lim_{x \to 0} \frac{\sqrt{x+1} - 1}{x}.
    • Hint: Multiply by the conjugate \sqrt{x+1} + 1.
  3. Continuity Check: Is f(x) = \begin{cases} x+1 & x < 1 \ 5 & x = 1 \ 3-x & x > 1 \end{cases}continuousatcontinuous atx=1?
    • Hint: Check the three-part DIC test.
  4. IVT Application: Show that f(x) = x^3 + x - 1 has at least one root on the interval [0, 1].
    • Hint: Compare f(0)andandf(1).
  5. Squeeze Theorem: Find \lim_{x \to 0} x^2 \sin(1/x).
    • Hint: Start with -1 \le \sin(1/x) \le 1.
Click for Quick Answers
  1. 4 (After canceling x-2)
  2. 1/2 (Rationalize numerator)
  3. No (Limit exists as 2, but f(1)=5; fails the Coincident test)
  4. Yes (f(0)=-1, f(1)=1; zero is between -1 and 1)
  5. 0 (Bound by -x^2andandx^2$)

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